Numbers spiral in a triangular pattern...

Hello again...

After showing you my number's spiral in a rectangular pattern, now I would like to show you in a triangular pattern. For ex, if your input is 4, then the output pattern would be:

         01
      12 13 02
  11  16 15 14 03
10 09 08 07 06 05 04

Hope you will find the code interesting...

#include
int main()
{
 int i, i2, j, k, l=1, m, n, o, p, q, r, s, sq, f[20][20];
 char fl='f';
 printf("Enter a number : ");
 scanf("%d",&n);
 sq = n * n;

 for(j=1;j<=n;j++)
 {
  for(i=1;i<=((2*n) - 1);i++)
   f[j][i] = 0;
 }
 i = n;
 i2 = 1;
 while(l<=sq)
 {
    if(fl == 'f')
    {
     f[i2][i] = l; 
     i2++;
     i++;

     if(f[i2][i]!=0 || i2>n)
     {
       i2 = i2 - 1;
       i = i - 1 - 1;
       fl = 'b';
     }
     l++;
    }
    else if(fl == 'b')
    {
     f[i2][i] = l;
     i2 = i2;
     i = i - 1;
     if(f[i2][i] != 0 || i<=0)
     {
      fl = 'u';
      i2--; 
      i = i + 1 + 1;
     }
     l++;
    }
    else if(fl == 'u')
    {
     f[i2][i] = l;
     i2--;
     i = i + 1;
     if(f[i2][i] != 0)
     { 
      fl = 'f'; 
      i2 = i2 + 1;
      i = i -1 + 1;
     }
     l++;
    }
 }
 int z = 0, tt=1, kl;
 for(j=1; j<=n; j++)
 {
  for(kl=1;kl<=((2*n) - 1);kl++){
  if(f[j][kl] != 0)
  {
    if(f[j][kl] <10)
      printf("0%d   ",f[j][kl]);
    else
      printf("%d   ",f[j][kl]);

  }
  else
   printf("          ");
  }
  
  printf("\n\n");
  
 }
 return 0;
}

Byeee